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Easy

Question

A solid cylinder of mass M and radius R rotates about its axis with angular speed ω. Its rotational kinetic energy is

  1. M R squared omega squared
  2. 1 over 8 M R squared omega squared
  3. 1 fourth M R squared omega squared
  4. 1 half M R squared omega squared

The correct answer is: 1 fourth M R squared omega squared


    Moment of inertia of the solid cylinder about its axis is
    I equals fraction numerator M R squared over denominator 2 end fraction
    therefore Rotational kinetic energy of the cylinder is

    K equals 1 half I omega squared equals 1 half fraction numerator M R squared over denominator 2 end fraction omega squared equals 1 fourth M R squared omega squared

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