physics
mechanics
Easy

Question

A wheel of moment of inertia 2.0 cross times 10 cubed kgm squared is rotating at uniform angular speed of 4 rads to the power of negative 1 end exponent. What is the torque required to stop it in one second.

  1. 2.0 cross times 10 cubed Nm
  2. 0.5 cross times 10 cubed Nm
  3. 8.0 cross times 10 cubed Nm
  4. none of these

The correct answer is: 8.0 cross times 10 cubed Nm


    alpha equals omega over t equals 4 over 1 equals 4 rad divided by straight s squared

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