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Easy

Question

$A space b a l l space o f space m a s s space 0.1 space K g. space i s space w h i r l e d space i n space a space h o r i z o n t a l space c i r c l e space o f space r a d i u s space 1 space m. space b y space m e a n s space o f space a space s t r i n g space a t space a n space i n i t i a l space s p e e d space o f space 10 space R. P. M. space space K e e p i n g space t h e space r a d i u s space c o n s tan t comma space t h e space t e n s i o n space i n space t h e space s t r i n g space i s space r e d u c e d space t o space o n e space q u a r t e r space o f space i t s space i n i t i a l space v a l u e. space space T h e space n e w space s p e e d space i s$

$14 r . p . m .$
$5 r . p . m .$
$20 r . p . m .$
$10 r . p . m .$

The correct answer is: $5 r . p . m .$

$square root of 3 m g not stretchy rightwards double arrow v equals square root of 2 g l left parenthesis 1 minus cos invisible function application theta right parenthesis end root therefore m g plus fraction numerator m v squared over denominator l end fraction$

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