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physics

mechanics

Easy

Question

Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radii $8 pi m rightwards arrow over short leftwards arrow divided by rightwards arrow over short leftwards arrow s squared$ and $equals 4 pi squared n squared r equals 4 pi squared open parentheses 1 half close parentheses squared cross times 4 equals 4 pi squared$ such that their periods are the same. Then the ratio between their centripetal acceleration is

$ω = \sqrt{\frac{p \times A}{m r}} = \sqrt{\frac{4.8 \times 10^{7} \times 10^{- 6}}{10 \times 0.3}}$
$m ω^{2} r$
$m ω^{2} r = p \times A$
$ω = 4 r a d / s e c$

The correct answer is: $m ω^{2} r$

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