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      physics
      mechanics
      Easy

      Question

      T w o m a s s e s T subscript 0 a n d T subscript 0 divided by 2 a r e a t t a c h e d t o a v e r t i c a l a x i s b y w e i g h t l e s s t h r e a d s o f c o m b i n e d
l e n g t h 4 T subscript 0. T h e y a r e s e t i n r o t a t i o n a l m o t i o n i n a h o r i z o n t a l p l a n e a b o u t t h i s a x i s w i t h c o n s t a n t
a n g u l a r v e l o c i t y 8 T subscript 0. I f t h e t e n s i o n s i n t h e t h r e a d s a r e t h e s a m e d u r i n g m o t i o n comma
t h e d i s t a n c e o f T subscript 0 equals m R omega subscript 0 superscript 2 f r o m t h e a x i s i s

      1. equals 8 T subscript 0
      2. 3.14 m divided by s
      3. T equals m left parenthesis 2 R right parenthesis left parenthesis 4 omega subscript 0 superscript 2 right parenthesis equals 8 m R omega subscript 0 superscript 2
      4. m divided by s

      The correct answer is: equals 8 T subscript 0


        I f space t h e space b o t h space m a s s space a r e space r e v o l v i n g space a b o u t space t h e space a x i s space y y apostrophe space a n d space t e n s i o n space i n space b o t h space t h e
t h r e a d s space a r e space e q u a l space t h e n
table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell space of 1em table attributes columnspacing 1em rowspacing 4 pt end attributes row cell straight m divided by straight s end cell row cell ⇒= fraction numerator text  Total displacement  end text over denominator time end fraction equals fraction numerator 2 m over denominator 1 s end fraction equals 2 ms to the power of negative 1 end exponent end cell end table end cell row cell not stretchy rightwards double arrow omega end cell end table

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