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physics

mechanics

Easy

Question

In a satellite if the time of revolution is T, then kinetic energy is proportional to

$\frac{1}{T}$
$\frac{1}{T^{2}}$
$\frac{1}{T^{3}}$
$T^{- 2 / 3}$

The correct answer is: $T^{- 2 / 3}$

$text Time period end text T proportional to r to the power of 3 divided by 2 end exponent not stretchy rightwards double arrow r proportional to T to the power of 2 divided by 3 end exponent text and Kinetic energy end text proportional to 1 over r proportional to 1 over T to the power of 2 divided by 3 end exponent proportional to T to the power of negative 2 divided by 3 end exponent$

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