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physics

mechanics

Easy

Question

A force F acts tangentially at the highest point of a solid cylinder of mass m kept on a rough horizontal plane. If the cylinder rolls without slipping, find the acceleration of the center of cylinder.

F
F/2
F/3
F/4

The correct answer is: F/3

$table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell F equals m a not stretchy rightwards double arrow a equals F divided by m end cell row cell tau subscript 0 equals F r equals I subscript 0 alpha not stretchy rightwards double arrow F r equals 1 half m r squared alpha not stretchy rightwards double arrow r alpha equals fraction numerator 2 F over denominator m end fraction end cell end table text since end text a less than r alpha comma text friction will act forward end text F plus f equals m a horizontal ellipsis left parenthesis i right parenthesis comma tau subscript 0 equals left parenthesis F minus f right parenthesis r equals I subscript 0 equals 1 half m r squared alpha text (ii) and For pure rolling, end text a equals r alpha horizontal ellipsis text (iii) end text F r o m space left parenthesis i i right parenthesis space a n d space left parenthesis i i i right parenthesis$

$A d d i n g space left parenthesis i right parenthesis space a n d space left parenthesis i v right parenthesis comma space w e space g e t table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell 2 F equals 3 over 2 m a not stretchy rightwards double arrow a equals fraction numerator 4 F over denominator 3 m end fraction end cell row cell F plus f equals m a equals m cross times fraction numerator 3 F over denominator 3 m end fraction equals fraction numerator 4 F over denominator 3 end fraction semicolon f equals F over 3 end cell row cell tau subscript A equals F cross times 2 R equals I subscript A alpha equals open parentheses 1 half m R squared plus m R squared close parentheses alpha end cell row cell a equals R alpha equals fraction numerator 4 F over denominator 3 m end fraction end cell end table text Let friction act for ward end text F plus f equals m a subscript c comma m end subscript equals fraction numerator 4 F over denominator 3 end fraction not stretchy rightwards double arrow f equals F over 3$

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A solid sphere of mass M and radius R is placed in a rough horizontal surface. It is struck by a horizontal cue struck at a height h above the surface. The value of h so that the sphere performs pure rolling motion immediately after it has been hit is

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A disc is at rest at the top of a rough inclined plane. It rolls without slipping. At the bottom of inclined plane there is a vertical groove. the minimum height of incline required is

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A horizontal force F is applied through the center of mass of a solid sphere of mass m and radius R which lies on a horizontal rough surface. If the sphere rolls without slipping, the acceleration of the center of mass of the sphere will be $open parentheses g equals 10 m divided by s squared close parentheses$

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$straight A space uniform space rod space of space mass space straight M equals 2 kg space and space length space straight L space is space suspended space by space two space smooth space hinges space 1 space and space 2 space as space shown space in space figure. space straight A space force space straight F equals 4 straight N space is space applied space downward space at space straight a space distance space straight L divided by 4 space from space hinge space 2. space Due space to space the space application space of space force space straight F comma space hinge space 2 space breaks. space At space this space instant space comma space applied space force space straight F space is space also space removed. space The space rod space starts space to space rotate space downward space about space hinge space 1. space open parentheses g equals 10 m divided by s squared close parentheses$

$The space reaction space at space hinge space 1 comma space just space after space breaking space of space hinge space 2 comma space is space$

$straight A space uniform space rod space of space mass space straight M equals 2 kg space and space length space straight L space is space suspended space by space two space smooth space hinges space 1 space and space 2 space as space shown space in space figure. space straight A space force space straight F equals 4 straight N space is space applied space downward space at space straight a space distance space straight L divided by 4 space from space hinge space 2. space Due space to space the space application space of space force space straight F comma space hinge space 2 space breaks. space At space this space instant space comma space applied space force space straight F space is space also space removed. space The space rod space starts space to space rotate space downward space about space hinge space 1. space open parentheses g equals 10 m divided by s squared close parentheses$

$The space reaction space at space hinge space 1 comma space just space after space breaking space of space hinge space 2 comma space is space$

PhysicsMechanics

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$straight A space uniform space rod space of space mass space straight M equals 2 kg space and space length space straight L space is space suspended space by space two space smooth space hinges space 1 space and space 2 space as space shown space in space figure. space straight A space force space straight F equals 4 straight N space is space applied space downward space at space straight a space distance space straight L divided by 4 space from space hinge space 2. space Due space to space the space application space of space force space straight F comma space hinge space 2 space breaks. space At space this space instant space comma space applied space force space straight F space is space also space removed. space The space rod space starts space to space rotate space downward space about space hinge space 1. space open parentheses g equals 10 m divided by s squared close parentheses$

$The space reaction space at space hinge space 1 comma space before space space hinge space 2 space breaks comma space is space$

$straight A space uniform space rod space of space mass space straight M equals 2 kg space and space length space straight L space is space suspended space by space two space smooth space hinges space 1 space and space 2 space as space shown space in space figure. space straight A space force space straight F equals 4 straight N space is space applied space downward space at space straight a space distance space straight L divided by 4 space from space hinge space 2. space Due space to space the space application space of space force space straight F comma space hinge space 2 space breaks. space At space this space instant space comma space applied space force space straight F space is space also space removed. space The space rod space starts space to space rotate space downward space about space hinge space 1. space open parentheses g equals 10 m divided by s squared close parentheses$

$The space reaction space at space hinge space 1 comma space before space space hinge space 2 space breaks comma space is space$

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$straight A space body space of space mass space straight M space and space radius space straight R space is space as space shown space in space figure space. space The space body space can space be space straight a space ring space comma space straight a space disc comma space straight a space hollow space sphere space or space straight a space solid space I subscript x comma I subscript y. space space and space I subscript z space space are space the space moments space of space inertia space about space straight x comma straight y space and space straight z space axis space respectively. space Origin space coincides space with space centre space of space mass space of space the space body.$

Column I
Column II

i. $I subscript x equals I subscript y equals I subscript z$
a. possible for ring or disc

ii. $I subscript x equals I subscript y plus I subscript z$
b. possible for hollow sphere or solid sphere

iii. $I subscript y equals I subscript z plus I subscript x$
c. possible for all of the bodies mentioned

iv. $I subscript z equals I subscript x plus I subscript y$
d. not possible for any of the body mentioned

$straight A space body space of space mass space straight M space and space radius space straight R space is space as space shown space in space figure space. space The space body space can space be space straight a space ring space comma space straight a space disc comma space straight a space hollow space sphere space or space straight a space solid space I subscript x comma I subscript y. space space and space I subscript z space space are space the space moments space of space inertia space about space straight x comma straight y space and space straight z space axis space respectively. space Origin space coincides space with space centre space of space mass space of space the space body.$

Column I
Column II

i. $I subscript x equals I subscript y equals I subscript z$
a. possible for ring or disc

ii. $I subscript x equals I subscript y plus I subscript z$
b. possible for hollow sphere or solid sphere

iii. $I subscript y equals I subscript z plus I subscript x$
c. possible for all of the bodies mentioned

iv. $I subscript z equals I subscript x plus I subscript y$
d. not possible for any of the body mentioned

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Two particles A and B of mass m each, are joined by a rigid massless rod of length l. A particle P of mass m, moving with speed u normal to AB, strikes A and stick to it. The centre of mass of the 'A + B + P' system after collision is C. If u = 4m/s, m = 3 kg, l = 3 m, then (All quantities in column are in SI units)

Two particles A and B of mass m each, are joined by a rigid massless rod of length l. A particle P of mass m, moving with speed u normal to AB, strikes A and stick to it. The centre of mass of the 'A + B + P' system after collision is C. If u = 4m/s, m = 3 kg, l = 3 m, then (All quantities in column are in SI units)

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$In space Column space straight I comma space information space about space the space force left parenthesis straight s right parenthesis space acting space on space straight a space body space is space mentioned comma space while space in space Column space II space information space about space the space motion space of space straight a space body space is space given. space Match space the space entries space in space Column space II space with space the space entries space in space Column space straight I.$

Column I
Column II

i. A single force through centre of mass
a. Rotational motion

ii.Equal and opposite forces separated by non-zero distance
b. Translation motion

iii. Equal and opposite forces acting at the same point
c. No motion

iv. A single force not through centre of mass
d. Centre of mass performs translatory motion

$In space Column space straight I comma space information space about space the space force left parenthesis straight s right parenthesis space acting space on space straight a space body space is space mentioned comma space while space in space Column space II space information space about space the space motion space of space straight a space body space is space given. space Match space the space entries space in space Column space II space with space the space entries space in space Column space straight I.$

Column I
Column II

i. A single force through centre of mass
a. Rotational motion

ii.Equal and opposite forces separated by non-zero distance
b. Translation motion

iii. Equal and opposite forces acting at the same point
c. No motion

iv. A single force not through centre of mass
d. Centre of mass performs translatory motion

PhysicsMechanics

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$From space straight a space uniform space disc space of space mass space straight M space and space radius space straight R comma space straight a space concentric space disc space of space radius space straight R divided by 2 space is space cut space out. space For space the space remaining space space annular space disc colon I subscript 1 space space space is space the space moment space of space inertia space about space axis space ‘ 1 ’ comma space space I subscript 2 space about space ‘ 2 ’ comma space space space space I subscript 3 italic space about space space ‘ 3 ’ comma space and space I subscript 4 space space space about space ‘ 4 ’. space Axes space ‘ 1 ’ space and space ‘ 2 ’ space are space perpendicular space to space the space disc space and space ‘ 3 ’ space and space ‘ 4 ’ space are space in space the space plane space of space the space disc. space Axes space ‘ 2 ’ comma ’ 3 ’ space and space ‘ 4 ’ space intersect space at space straight a space common space point. space Match space the space following space$

Column – I

Column – II

i. $I subscript 1$ is equal to
a. $21 over 32 M R squared$

ii. $I subscript 2$ is equal to
b. $I subscript 1 divided by 2$

iii. $I subscript 3 plus I subscript 4$ is equal to
c. $15 over 32 M R h 2$

iv. $I subscript 2 minus I subscript 3$ is equal to
d. none of these

$From space straight a space uniform space disc space of space mass space straight M space and space radius space straight R comma space straight a space concentric space disc space of space radius space straight R divided by 2 space is space cut space out. space For space the space remaining space space annular space disc colon I subscript 1 space space space is space the space moment space of space inertia space about space axis space ‘ 1 ’ comma space space I subscript 2 space about space ‘ 2 ’ comma space space space space I subscript 3 italic space about space space ‘ 3 ’ comma space and space I subscript 4 space space space about space ‘ 4 ’. space Axes space ‘ 1 ’ space and space ‘ 2 ’ space are space perpendicular space to space the space disc space and space ‘ 3 ’ space and space ‘ 4 ’ space are space in space the space plane space of space the space disc. space Axes space ‘ 2 ’ comma ’ 3 ’ space and space ‘ 4 ’ space intersect space at space straight a space common space point. space Match space the space following space$

Column – I

Column – II

i. $I subscript 1$ is equal to
a. $21 over 32 M R squared$

ii. $I subscript 2$ is equal to
b. $I subscript 1 divided by 2$

iii. $I subscript 3 plus I subscript 4$ is equal to
c. $15 over 32 M R h 2$

iv. $I subscript 2 minus I subscript 3$ is equal to
d. none of these

PhysicsMechanics

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$End space straight A space space of space straight a space rod space AB space is space being space pulled space on space the space floor space with space straight a space constant space velocity space space v subscript 0 space as space shown. space Taking space the space length space of the space rod space as space l space comma space at space an space instant space when space the space rod space makes space an space angle space 37 to the power of 0 space space with space the space horizontal comma space calculate space space$

$The space angular space velocity space of space the space end space$

$End space straight A space space of space straight a space rod space AB space is space being space pulled space on space the space floor space with space straight a space constant space velocity space space v subscript 0 space as space shown. space Taking space the space length space of the space rod space as space l space comma space at space an space instant space when space the space rod space makes space an space angle space 37 to the power of 0 space space with space the space horizontal comma space calculate space space$

$The space angular space velocity space of space the space end space$

PhysicsMechanics

Mechanics

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$End space straight A space space of space straight a space rod space AB space is space being space pulled space on space the space floor space with space straight a space constant space velocity space space v subscript 0 space as space shown. space Taking space the space length space of the space rod space as space space comma space at space an space instant space when space the space rod space makes space an space angle space 37 to the power of 0 space space with space the space horizontal comma space calculate$

$The space velocity space of space end space straight B$

$End space straight A space space of space straight a space rod space AB space is space being space pulled space on space the space floor space with space straight a space constant space velocity space space v subscript 0 space as space shown. space Taking space the space length space of the space rod space as space space comma space at space an space instant space when space the space rod space makes space an space angle space 37 to the power of 0 space space with space the space horizontal comma space calculate$

$The space velocity space of space end space straight B$

PhysicsMechanics

Mechanics

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$straight A space uniform space rod space of space mass space straight M equals 2 kg space and space length space straight L space is space suspended space by space two space smooth space hinges space 1 space and space 2 space as space shown space in space figure. space straight A space force space straight F equals 4 straight N space is space applied space downward space at space straight a space distance space straight L divided by 4 space from space hinge space 2. space Due space to space the space application space of space force space straight F comma space hinge space 2 space breaks. space At space this space instant space comma space applied space force space straight F space is space also space removed. space The space rod space starts space to space rotate space downward space about space hinge space 1. space open italic left parenthesis g equals 10 m divided by s squared close parentheses$

$The space reaction space at space hinge space 1 comma space just space after space breaking space of space hinge space 2 comma space is space$

$straight A space uniform space rod space of space mass space straight M equals 2 kg space and space length space straight L space is space suspended space by space two space smooth space hinges space 1 space and space 2 space as space shown space in space figure. space straight A space force space straight F equals 4 straight N space is space applied space downward space at space straight a space distance space straight L divided by 4 space from space hinge space 2. space Due space to space the space application space of space force space straight F comma space hinge space 2 space breaks. space At space this space instant space comma space applied space force space straight F space is space also space removed. space The space rod space starts space to space rotate space downward space about space hinge space 1. space open italic left parenthesis g equals 10 m divided by s squared close parentheses$

$The space reaction space at space hinge space 1 comma space just space after space breaking space of space hinge space 2 comma space is space$

PhysicsMechanics

Mechanics

Physics

$straight A space uniform space rod space of space mass space straight M equals 2 kg space and space length space straight L space is space suspended space by space two space smooth space hinges space 1 space and space 2 space as space shown space in space figure. space straight A space force space straight F equals 4 straight N space is space applied space downward space at space straight a space distance space straight L divided by 4 space from space hinge space 2. space Due space to space the space application space of space force space straight F comma space hinge space 2 space breaks. space At space this space instant space comma space applied space force space straight F space is space also space removed. space The space rod space starts space to space rotate space downward space about space hinge space 1. space open italic left parenthesis g equals 10 m divided by s squared close parentheses$
$The space reaction space at space hinge space 1 comma space before space space hinge space 2 space breaks comma space is space$

$straight A space uniform space rod space of space mass space straight M equals 2 kg space and space length space straight L space is space suspended space by space two space smooth space hinges space 1 space and space 2 space as space shown space in space figure. space straight A space force space straight F equals 4 straight N space is space applied space downward space at space straight a space distance space straight L divided by 4 space from space hinge space 2. space Due space to space the space application space of space force space straight F comma space hinge space 2 space breaks. space At space this space instant space comma space applied space force space straight F space is space also space removed. space The space rod space starts space to space rotate space downward space about space hinge space 1. space open italic left parenthesis g equals 10 m divided by s squared close parentheses$
$The space reaction space at space hinge space 1 comma space before space space hinge space 2 space breaks comma space is space$

PhysicsMechanics

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