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physics

mechanics

Easy

Question

A cube of mass ‘m’ and side ‘a’ moving along with a constant speed as shown in figure. The magnitude of angular momentum of cube about z-axis would be

$\frac{m v_{0} b}{2}$
$\sqrt{3} \frac{m v_{0} (b - a)}{2}$
$m v_{0} (b - \frac{a}{2})$
$\frac{n v_{0} (b - a)}{2}$

The correct answer is: $\frac{m v_{0} b}{2}$

$table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell L equals m v r end cell row cell L equals m times v subscript 0 over 2 times b end cell row cell L equals fraction numerator m v subscript 0 b over denominator 2 end fraction end cell end table$

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PhysicsMechanics

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